Which of the ordered pairs is a solution for the equation 4x – 3y = 12?

Answer 1

let

x = 0

4x - 3y = 12

4(0) - 3y = 12

0 - 3y = 12

- 3y = 12

Divide both sides of the equation by - 3

- 3y / - 3 = 12 / - 3

y = 12 / - 3

y = - 4

ordered pair

(0, - 4)

- - - - - - -

Let

y = 0

4x - 3y = 12

4x - 3(0) = 12

4x - 0 = 12

4x = 12

Divide both sides of the equation by 4

4x / 4 = 12 / 4

x = 12 / 4

x = 3

Ordered pair

(3, 0)

- - - - - - - -s-

Answer 2

Equation of the line is 4x-3y = 12

put x=0 in the equation then -3y=12
y=12/-3
y=-4
substitute y=-4 in the equation then
4x-3(-4)=12
4x+12=12
4x=12-12
4x=0
x=0
Therefore x=0 and y=-4
(0,-4) similarly put y=0 in equation then x=3 and y=0,(3,0)

therefore the ordered pairs are
{(0,-4),(3,0)}
verification:

0-3(-4)=12
12=12
hence verified

Answer 3

Check any ordered pair by remembering (x,y). So, if you had (2,5), you would substitute into the equation 4(2)+3(5)=12, and since 8+15 does not equal 12, the ordered pair of (2,5) would be incorrect.

Answer 4

4x – 3y =12
3y= 4x -12
x=1, 3y= (4x1-12), 3y=-8, y=-8/3=-2 2/3
x=2, 3y= (4x2-12), 3y=-4, y=-4/3=-1 1/3
x=3, 3y= (4x3-12), 3y= 0, y=0
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x=9, 3y= (4x9-12), 3y=24, y=24/3=8
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Answer 5

(3,-2) Divide the 1st equation by skill of two, so which you have x+y=one million. next, get the x on one area, so which you have x=one million-y. Plug this into the 2nd equation, so which you have one million-y-y=5, which simplifies to one million-2y=5. resolve for y, so which you have -2y=4 and then y=-2. Plug that into the 1st equation, so which you have 2x+2(-2)=2 and then x=3!

Answer 6

This canbe done by giving values to x,say 0,1,-1,2,-2.,we find the value of y
so let us have x=0,so
4x-3y=12
or 4.0-3y=12
or -3y=12
or y=-12/3=-4 ,so one ordered pair is (0,-4),similarly we can have more pairs ans

Answer 7

4x=12

4x/4=12/4

x=3

-3y=12

-3y/-3=12/-3

y=-4

ordered pairs
(3,-4)

Answer 8

as of the initial post, there are infinite # of solutions to this problem...

asker has not posted possible ordered pairs..

Answer 9

are there choices, e.g., (6,4)?