4x - y = 6
3x + y = 1
A- (-2,1)
B- (1,-2)
C- (5,14)
D- (2,2)
2007-07-27 06:35:18 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Well I can't do the graph for you on here. You'll have to do that yourself.
Solve each for y.
y = 4x - 6
slope = 4
y-int = (0, 6)
y = -3x + 1
slope = -3
y-int = (0, 1)
They intersect at B- (1,-2)
2007-07-27 06:38:28 · answer #1 · answered by Becky M 4 · 0⤊ 0⤋
4x - y = 6
3x + y = 1
For the 1st equation when x = 0 y= -6, and when y=0, x=3/2
So plot the points (0,-6) and (3/2,0) and draw a line through these two points extending the line as much as you wish.
Now do the same with the 2nd equation and you should get the points (0,1) and (1/3,0). Draw a line through these 2 points and extend as necessary to intersect the first line. The point of intersection of the two lines is the solution.
If you have graphed accurately, the two lines should intersect at the point (1,-2)
2007-07-27 06:49:08 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
for graphical method,u just plot these lines on a graph.after plotting them,u will get an intersection point of these two lines.That intersection point is the soluyion of the given equations.in this case,it is (1,-2)
2007-07-27 06:45:16 · answer #3 · answered by aviral17 3 · 0⤊ 0⤋
MIT open courseware has a complete call on linear algibra it is great. Getting Yahoo answers to do you homework is not.
Watch the video lectures he shows the grphing process very well.
2007-07-27 06:39:44 · answer #4 · answered by Anonymous · 1⤊ 0⤋
Dude, let me guess: Summer school? Sucks, eh? I just finished mine like 2 minutes ago.
Probably not summer school though...
2007-07-27 06:38:10 · answer #5 · answered by Untitled Sabrina Project 4 · 0⤊ 2⤋