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Roberto invested some money at 6%, and then invested $5000 more than twice this amount at 11%. His total annual income from the two investments was $4470. How much was invested at 11%?

2007-07-27 05:43:31 · 2 answers · asked by koka 1 in Science & Mathematics Physics

2 answers

the annual return is i*c

setting up the algebra
c*.06+(C*2+5000)*.11=4470

c*(.06+.22)=4470-5000*.11
c=(4470-5000*.11)/.28
c=14000

j

2007-07-27 05:51:35 · answer #1 · answered by odu83 7 · 0 1

Do your own homework. You might actually learn something.

2007-07-27 12:49:18 · answer #2 · answered by ZikZak 6 · 0 0

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