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If a sample of water has a pH of 5.2 due to dissolved carbon dioxide forming the weak acid, H2CO3, with a Ka1= 4.3 * 10^-7, what is the concentration in M. of H2CO3 at equilibrium?

2007-07-27 05:14:19 · 2 answers · asked by cbrice9 1 in Science & Mathematics Chemistry

2 answers

pH = 5.2
[H+] = 10^-5.2 = 6.31 x 10^-6 M
The equilibrium is
CO2 + H2O <---> H+ + HCO3-
[H+] = [ HCO3-]
K = 4.3 x 10^-7 =( 6.31 x 10^-6)^2 / x
x = [HCO3-] = 9.26 x 10^-5 M

2007-07-27 06:28:48 · answer #1 · answered by Dr.A 7 · 0 0

You mean Molarity ??????

2007-07-27 12:39:38 · answer #2 · answered by ag_iitkgp 7 · 0 1

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