how do you calculate the mass of the following. (Avogadro's number = 6.022E23 particles/mol).
oxygen in 5.52E+22 molecules SO3
2007-07-26 19:05:02 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
There are 3 * 5.52 * 10^22 = 1.656*10^23 atoms of oxygen in that amount of SO3; 6.022*10^23 atoms of oxygen will have a mass of 16 grams. Therefore, the mass of oxygen is (1.656*10^23 / 6.022*10^23)*16 = 0.275*16 = 4.4 grams
2007-07-26 19:14:26 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
convert molecules into moles
moles SO3=5.52E+22 molecules/6.022E23molecules/moles
=0.091664 moles SO3
then by stoichiometric ratio (1.5moles Oxygen/1 mole SO3) , oxygen referring to O2, we can get mole of oxygen and convert it to mass by multiplying to **** molecular wt. (32g/mol)
mass O2=0.0917664moles SO3x(1.5moles O2/1moleSO3)x(32g/mol)
=4.40grams of oxygen
2007-07-27 02:21:36 · answer #2 · answered by Divine C 2 · 0⤊ 0⤋
i dont understand what this E is
O2 in 5,52 what???????
2007-07-27 02:13:44 · answer #3 · answered by mikrodimitris 3 · 0⤊ 0⤋