would you please help me with this problem,
18.0 g oxygen reacts with sufficient nitrogen to make 25.9 g of nitrogen dioxide according to the following reaction:
O2(g) + N2(g)----> 2NO2(g)
If the reaction goes to completion, how much nitrogen reacted?
2007-07-26 18:17:19 · 4 answers · asked by lulu 1 in Science & Mathematics ➔ Chemistry
It's stoichiometry....... Convert to moles, then use the ratios to find the answer.....
2007-07-26 18:20:53 · answer #1 · answered by gkltdd 4 · 0⤊ 0⤋
First you convert 18 g of oxygen to moles by dividing by 32. Then convert 25.9 g of NO2 to moles by dividing by 46 (about 0.55 moles).
Now, from the equation, you need 0.275 moles of nitrogen to form 0.55 moles of NO2. So multiply 0.275 by 28 to get the grams of nitrogen entering into the reaction.
BTW: Note that you have more oxygen around than is needed to form 25.9 g of NO2, but the problem is worded to make nitrogen the limiting reagent.
2007-07-27 01:27:31 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
Firstly balance the equation:
it bcoms
2O2+N2=2NO2
according to the reaction,
2 moles of oxyagen reacts wid 1 mole of nitrogen to give 2 molse of NO2.
this means,
64g of O2 reacts with 28g of N2 to form 92g of NO2
now for 64d of O2 to react,we require 28 of N2
so for 18g of O2 to react,we will require 7.8g of N2
2007-07-27 01:29:46 · answer #3 · answered by aviral17 3 · 0⤊ 0⤋
Wow. I'm lost at the first sentence!!!
2007-07-27 01:23:15 · answer #4 · answered by 7 Habits 3 · 0⤊ 0⤋