i dont get how to write this balanced equations, can u help?

Question

"Write balanced equations for the complete combustion of these hydrocarbons. List the hydrocarbon as the first reactant. List the carbon containing product as the first product. Enter formulas with coefficients without a space between the formula and its coefficient. In this question, leave off coefficients of 1 (1 is implied)."

1) propane, C3H8
____ + ____ -----> ____ + ____

2) benzene, C6H6
___ + ___ --------> ____ + _____

3) octane, C8H18
___ + ____ ------> ____ + ____

Answer 1

its quite easy to balance such equations.I will demonstrate wid the first one.
C3H8+O2=CO2+H2O
This is the general combustion reaction.u can replace C3H8 wid other combustible materials.
it bcomes
C3H8+O2=3CO2+H2O[Now C is balanced]
now balance H
so it bcoms
C3H8+O2=3CO2+4H2O[H is balacd]
now O
it bcoms
C3H8+5O2=3CO2+4H2O

similarly the others one can b done.Remeber the general combustion equation

Answer 2

1) H2SO4 + 2NaOH => Na2SO4 + 2H2O 2) CH4 + 2O2 => CO2 + 2H2O 3) 2AgNo3 + Cu => Cu(NO3)2 + 2Ag 4) Mg + ZnSO4 => MgSO4 + Zn As to the state symbols - Rreaction 1 can take place in aqueous solution Reaction 2 is between gases. We can assume the water condenses into the liquid phase as the temperature drops, but that's your choice Reactions 3 and 4 are between solutions and solid metals and yield solutions and solid metals With the above hints, you should be able to insert state symbols into the equations...........

Answer 3

You wind up with CO2 and H2O. The number of CO2 equals the number of carbons in the hydrocarbon molecule. The number of H2O equals ONE-HALF the number of hydrogens in the molecule. For each CO2, you need 1 mole of O2, and for each H2O, you need 1/2 mole of O2.

With that in hand, you can figure it out for yourself.

Answer 4

general equation for combustion reaction of hydrocarbon

hydrocarbon + O2 --> CO2 + H2O

balance the equation.

Answer 5

1...C3H8 + 5(O2) ===> 3CO2 + 4H2O
2...2C6H6 + 15(O2) ===> 12CO2 + 6H20
3...2C8H18 + 25(O2) ===> 16CO2 + 18H2O