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what do you get when you divide 5a^2+6a-9 into 25a^4+19a^2-a-78

2007-07-26 16:04:31 · 2 answers · asked by percy m 1 in Science & Mathematics Mathematics

2 answers

use long division
25a^4+19a^2-a-78 =
(5a^2+6a-9)(5a^2-6a +20) + (-175a+102)

5a^2+6a-9 )25a^4+19a^2-a-78 (5a^2-6a +20
less 25a^4+30a^3-45a^2
-------------------------------------------------------------------
-30a^3 +64a^2-a-78
less -30a^3-36a^2+54a
----------------------------------------------------------
100a^2 -55a-78
less 100a^2+120a-180
-----------------------------------------------
-175a+102

so remainder is -175a+102

2007-07-26 16:46:58 · answer #1 · answered by sweet n simple 5 · 0 0

You get 5a^2 -6a - 20 with a remainder of 65a-258.
Just use long division or synthetic division.

2007-07-26 23:14:41 · answer #2 · answered by ironduke8159 7 · 0 0

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