Can someone please help me solve this please?

Question

The electron gun in a television tube is used to accelerate electrons( mass of 9.10939x 10^-31 kg and charge of -1.60218X10^-19 C) from rest to 2 X 10^7 m/s within a distance of 5.5 cm. What is the electric field require? Answer in units of N/C.


I got 2.2 x10-13 but im not sure if I did it right can someone check me please

Answer 1

Work = KE
so Vq = 1/2 m v^2
=> V = 1/2 (9.11×10^-31) (2×10^7)^2 / (1.602×10^-19)
= 1137 V
and E = V/d = 1137 / 0.055 = 2.07×10^4 N/C.