The electron gun in a television tube is used to accelerate electrons( mass of 9.10939x 10^-31 kg and charge of -1.60218X10^-19 C) from rest to 2 X 10^7 m/s within a distance of 5.5 cm. What is the electric field require? Answer in units of N/C.
2007-07-26 13:48:59 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
v^2 – u^2 = 2 a s .
v^2 = 2 a s. since u = 0.
a = v^2 / [ 2s ]
-----------------------------------
F = ma = mv^2 / [ 2s ]
-----------------------------------------
Electric field intensity E = F / q
E = mv^2 / [ 2 q s ]
-------------------------------------------
= [ 9.10939x 10^-31 ] * [ 2 X 10^7 ] ^2 / [ 2 * 1.60218X10^-19 * 0.055]
E = 20675 N/C
2007-07-26 15:48:05 · answer #1 · answered by Pearlsawme 7 · 0⤊ 0⤋
Work from what you know to what you don't know. Use kinematics to figure out what magnitude of constant acceleration you need. Use Newton's second law to figure how much constant force you need to accomplish that acceleration. Use Coulomb's law to do the rest.
2007-07-26 14:07:02 · answer #2 · answered by Frank N 7 · 0⤊ 0⤋
Can I do his homework for him?? Please!!??
2007-07-26 14:59:15 · answer #3 · answered by muddypuppyuk 5 · 0⤊ 0⤋