solve the equation by using factoring 8x^3 - 32x=0?

Answer 1

8 x (x ² - 4) = 0
8 x (x - 2) (x + 2) = 0
x = - 2 , x = 0 , x = 2

Answer 2

8x^3 - 32X = 0.

1) look for common factors. This is the easiest to start with.

8x(x^2 - 4) = 0.

2) Look for special products. X^2 -4 is a difference of two squares, ie, x^2 - 2^2, so we continue factoring as:

8x(x+2)(x-2) = 0.

Now we see

8x = 0 | x+2 = 0 | x-2 = 0, where the bar means OR.

x = 0 | x=-2 | x=2.

done.

Answer 3

factor out 8x

8x (x^2 - 4) = 0

factor the rest by using the difference of perfect square formula:

a^2 - b^2 = (a - b) (a + b)

8x (x - 2) (x + 2) = 0

x = 0, 2 or -2

Answer 4

8x^3-32x=0
8x(x^2-4)=0
8x=0 , x^2-4)=0

x=0/8, (x+2)(x-2)=0

x=0, x+2=0, x-2=0

x=0, x= -2, x=2

Remember 0/8=0 and 8/0=undefined

Answer 5

8x^3-32x=0

Take out common factor:
8x(x^2-4)=0

Factor further:
8x(x+2)(x-2)=0

Set each part equal to 0 and solve.
8x=0
x=0

x+2=0
x=-2

x-2=0
x=2

So x=0, 2, or -2

Answer 6

8x^3 - 32x = 0
x(8x^2 - 32) = 0
8x(x^2 - 4) = 0
8x(x+2)(x-2) = 0

x = 0 or
x = 2 or
x = -2

Answer 7

8x^3-32x=0
8x(x^2-4)=0
8x(x+2)(x-2)=0
x={-2, 0, 2}

Answer 8

8x(x^2-4)=0
8x(x-2)(x+2)=0
sox=0 orx=2 orx=-2
s.s={0,2,-2}

Answer 9

8X*(X^2-4)
8X*(X-2)*X+2) = 0
X = 0
X= 2
X = -2