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Multiply. Simplify if possible.

z ^3 multiplied by 4 / 20z 2z^2

z / 10

1 / 10z

1 / 10

z^3 / 10z^2

2007-07-26 10:12:24 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

z^3 4 / 20z 2z^2
All z factors cancel.
4 / (20 * 2)
= 1/10.

2007-07-26 10:16:18 · answer #1 · answered by Anonymous · 0 0

If you mean z^3 * ( 4 / (20z 2z^2) ) and not z^3 * (4 / 20z) * 2z^2, then...

Remember the rules for exponents: x^a / x^b = x^(a-b), and x^a * x^b = x^(a+b). So here we have

z^3 * ( 4 / (20z 2z^2) )
z^3 * ( 1 / (5z 2z^2) )
z^3 * ( 1 / (10 z z^2) )
z^3 * ( 1 / (10 z^3) )
z^3 / (10 z^3)
(1/10) * z^(3-3)
(1/10) * z^(0)
(1/10) * 1
1/10

Another way of looking at this is that the z^3 "cancels" the three "z"s on the bottom.

2007-07-26 17:30:51 · answer #2 · answered by Anonymous · 0 0

I belive this is your problem:
Z^3(4/(20z2z^2))

First let's look at the intermost parenthises. You need to multilply everything together. Remember that the variables need to have the same base, but not the same exponent. Here the variables are both z's so we are fine.
20*z*2*z^2
20*2*z*z^2 (we can do this since it doesn't matter which order
you multiply numbers in according to the commutative
property)
40*z^3
40z^3

This expression is now simplified to z^3(4/40z^3)
What you need to do now is to simplify the next parenthises. You can divide both the top and bottom by 4 (which would be the same thing as dividing by 4/4 or 1). This will reduce the expression to z^3(1/10z^3)
You then need to multiply z^3 in, which will only multiply across the numerator
z^3/10z^3
Now both the top and bottom can be divided by their common term, z^3, which leaves you with the most simplified form of the expression.
1/10

2007-07-26 17:36:14 · answer #3 · answered by girl person 2 · 0 0

4 z ³ / 40 z ³ = 1 / 10

2007-07-26 17:53:54 · answer #4 · answered by Como 7 · 0 0

z ^3 * (4 / (20z 2z^2)) =
(4z^3)/(2z^2 * 20z) =
(4z^3)/(40z^3) =
4/40 =
1/10

2007-07-26 17:26:49 · answer #5 · answered by N E 7 · 0 0

4z / 200z^3 = 1/50z^2

2007-07-26 17:28:23 · answer #6 · answered by cwsoccer21 1 · 0 0

duhhhhhhhhhhhhh

2007-07-26 17:20:12 · answer #7 · answered by M. 2 · 0 1

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