help me answer this chemistry question question in the details?

Question

a chemist collects 416 mL of nitrogen gas OVER WATER at 60'c
and 677torr. what is the volume of the DRY GAS at STP if the vapor pressure of water at 60'c is 149torr

Answer 1

In such questions,
the partial pressure of dry gas=pressure of collected gas-vapour pressure of water=677-149=528torr.
Now use the formula,
416*528/333=760*V/273
V-is the required volume

Answer 2

Subtract the water vaor pressure from the total pressure to get the net pressure for the Nitrogen.

Now use the combined gas law to adjust to STP

P1V1/T1 = P2V2 / T2

You have P1 from above.
V1 = 416 mL
T1 = 60 C but you need Kelvin, so 333K

P2 = 760
T2 = 273 K
solve for V2