i need helppp!?

Question

okay so i have an algebra 2 final in like 2 hours and i need help with 2 problems, please help me as much as you can

x^2-2x-8=4

and

64x^4/3
_______
x^-2/3

all times ^ 1/2

i'm freaking out here!!!!!!!

Answer 1

x^2 - 2x - 8 - 4 = 0
x^2 - 2x - 12 = 0
The equation is Ax^2 + Bx + C = 0
And the solution x = [-B +/- SQRT(B^2 - 4*A*C)] / [2*A]
In this case: A = 1 ; B = -2 ; C = -12
x = [2 +/- SQRT(4 + 48)] / 2
x = 1 +/- SQRT(13)


64x^4/3
----------- = 64x^4/3 * x^2/3 = 64x^(4/3 + 2/3) = 64x^2
x^-2/3


Don't know what you want done with "all times ^ 1/2"