The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle.
A) 8 in. B) 9 in. C) 10 in. D) 7 in.
2007-07-26 06:41:58 · 2 answers · asked by Dawn M 1 in Science & Mathematics ➔ Mathematics
Perimeter Formula
P = 2L + 2W
Let
w = Width
2W + 8 = Length
64 = perimether
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64 = 2(2W + 8) + 2W
64 = 4W + 16 + 2W
64 = 6W + 16
64 - 16 = 6W + 16 - 16
48 = 6W
48/6 = 6W / 6
48/6 = W
8 = W
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The width is 8 inches
The length equals
2W + 8
2(8) + 8 =
16 + 8 =
24
The length is 24 inches
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2007-07-26 07:07:43 · answer #1 · answered by SAMUEL D 7 · 1⤊ 0⤋
L = 2W + 8
Perimeter = 2(L + W)
64 = 2(W + 8 + 2W)
32 = 3W + 8
W = 24/3
W = 8 inches
Width = 8 inches
Length = 2(8) + 8 = 24 inches
2007-07-26 13:46:00 · answer #2 · answered by Anonymous · 0⤊ 0⤋