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x^2-8x+16

Thank you!

2007-07-26 06:36:11 · 4 answers · asked by Brandon 1 in Science & Mathematics Mathematics

4 answers

x² - 8x + 16 = 0

x² - 4x - 4x + 16 = 0

x(x - 4) - 4(x - 4) = 0

(x - 4)(x - 4) = 0

- - - - - - -s-

2007-07-26 07:12:18 · answer #1 · answered by SAMUEL D 7 · 2 0

First and foremost set the equation equal to 0

x^2 - 8x + 16 = 0
Then by factoring...
(x - 4)(x - 4) = 0
Set each parenthesis equal to 0 and
x - 4 = 0
So you are forced to conclude
So x = 4

2007-07-26 13:40:32 · answer #2 · answered by Dan 2 · 0 0

x^2-8x+16
=(x)^2-2*x*4+(4)^2
=(x-4)^2

2007-07-26 13:39:56 · answer #3 · answered by alpha 7 · 1 0

(x-4)(x-4)

:)

2007-07-26 13:40:03 · answer #4 · answered by LIFE HATER 1 · 0 0

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