Let job consist of X units
Barry`s rate of work = (X / 4) units / hour
Mike`s rate of work = (X / 6) units / hour
Working together they complete
X / 4 + X / 6 units in 1 hour
3X / 12 + 2X / 12 units in 1 hour
5X / 12 units in 1 hour
Time for X units = X / [5X / 12 ] hours
Time = 12 / 5 hours
Time = 2 2/5 hours
Time = 2 h 24 min.
2007-07-27 07:14:02
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answer #1
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answered by Como 7
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To do the job together, it would take them 5 hours.
Barry can do 1/4 of the job in an hour, and Mike can do 1/6 of the job in an hour. If you add them together, you get 5/12 of an hour. Then you multiply by 12 to see how much it is totally, which is 5 hours.
2007-07-26 02:31:40
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answer #2
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answered by Anonymous
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Barry can do 1/4 of the job in 1 hour (or 3/12)
Mike can do 1/6 of the job in 1 hour (or 2/12)
In one hour they can do 5/12 of the job.
So, it would take them 12/5 hours to complete the job.
2007-07-26 02:30:45
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answer #3
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answered by miggitymaggz 5
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in 1 hour Barry will do 1/4 work and Mike will do 1/6 work
so total work in 1 hour = 1/4+1/6 = 5/12
so it will take 12/5 hours to do whole work i.e. 2 hours 24 minutes
2007-07-26 02:31:09
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answer #4
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answered by Anubarak 3
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(4 x 6) / ( 4 + 6) = 24 / 10 = 12 / 5
It will take 2 hours and 24 minutes.
2007-07-26 02:34:43
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answer #5
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answered by Don E Knows 6
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let the total work done in job be x;
barry work rate is x/4 work per hour.
mike's rate is x/6 work per hour
work done in one hour by both is x/6 + x/4
=10x/24=5x/12;
so time taken = x/(work rate)= 12/5 hours = 2.4 hours= 2 hours 24 mins
2007-07-26 02:31:22
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answer #6
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answered by S R 1
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12 hrs where Barry do 3 jobs while mike 2 jobs..
2007-07-26 02:31:01
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answer #7
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answered by echa r 1
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Rate Barry Works at: j/4hr
Rate Mike Works at: j/6hr
j/4hr + j/6hr = 3j/12hr + 2j/12hr
5j/12hr is their total rate.
Multiply by 12hr/5 to finish job.
12/5 hrs
2007-07-26 02:31:31
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answer #8
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answered by UnknownD 6
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10 days
2007-07-26 03:15:46
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answer #9
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answered by Anonymous
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