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11 answers

3x+3=51
51-3=48
48/3=16

x=16
16*2+3=35

so its 16 and 35

2007-07-26 00:54:48 · answer #1 · answered by Crispy (Chris P) 2 · 0 0

Let x be one of the integers. Since the larger integer is 3 more than twice the smaller integer, that makes the other integer 2x + 3.

Since the sum of the integers is 51,
x + (2x + 3) = 51
3x + 3 = 51
3x = 48
x = 16

That makes the first integer x = 16, and the second integer
2x + 3 = 2(16) + 3 = 35

16 and 35

2007-07-26 07:47:02 · answer #2 · answered by Puggy 7 · 0 0

Let the smaller integer be x.

The larger integer is thus (2x + 3).

The sum of the two integers is 51.

Thus, x + (2x +3) = 51

Open the brackets and collect the like terms.

x + 2x = 51 - 3

3x = 48

Divide by 3 on both sides to find x which is the value of the smaller integer.

x = 16

To find the value of the larger integer, substitute the value of x in (2x + 3).

2x + 3
= (2 x16) + 3
= 35

Therefore, the integers are 16 and 35.

2007-07-26 07:57:08 · answer #3 · answered by MO 2 · 0 0

let x be the smaller number, then the larger integer is 2x+3. Since the sum is 51, then x+2x+3 = 51 =>
3x = 48 => x=16. from this, the remaining is 16x2 +3= 35.
thus, you have 16 and 35.

2007-07-26 07:52:03 · answer #4 · answered by mikael 3 · 0 0

Let a and b be the two integers.

a + b = 51

a = 2b + 3

So, 2b + 3 + b = 51

3b = 51 - 3 = 48

b = 48/3 = 16

a = 2b + 3
= 32 + 3 = 35

So, 35 and 16 are the two integers.

2007-07-26 07:48:51 · answer #5 · answered by Swamy 7 · 0 0

Let smaller integer be x, then bigger integer is 3+2x.

Sum of both integers = x + (3+2x) = 52
3x+3=51
3x=48
x=16

The other integer is (3+2x)
=(3+2*16)
=35

The two integers are 16 & 35.

2007-07-26 07:47:55 · answer #6 · answered by Jain 4 · 0 0

16 and 35

2007-07-26 08:01:28 · answer #7 · answered by VanFiyai 3 · 0 0

sum means we will add the two numbers

lets call one number n, and based on the question the other number is two times n plus 3

number one = n

number two = 2n + 3

these two numbers add to 51
therefore

n + ( 2n+ 3) = 51

3n + 3 = 51

3n+3 -3 = 51 -3
3n = 48
n = 48/3

n= 16

therefore of one of the number is 16 the other number is twice 16 + 3

which is 16 x 2 + 3
which is 35

Therefore your numbers are 16 and 35

2007-07-26 07:53:31 · answer #8 · answered by Money Power R 2 · 0 0

[1] a+b=51
[2] a = 2b+3
Subtract [2] from [1]
b = -2b +48
So 3b = 48
so b = 16
so a = 35
.

2007-07-26 07:48:28 · answer #9 · answered by tsr21 6 · 0 0

35 & 16......total:35+16 =51
16*2=32 +3 =35.

2007-07-26 07:55:00 · answer #10 · answered by mehul m 1 · 0 0

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