I have been surfing the web for a while now in vain. Alternatively if someone you tell me where to get The Chinese Tarot Deck that would be great too!
Cheers!
PS: Amazon have some rediculous prices!
2007-07-24 23:29:54 · 7 answers · asked by Anonymous in Society & Culture ➔ Mythology & Folklore
Here is a couple of links where you can buy online or look on ebay
http://tarotpassages.com/goldendragon.htm
http://www.aeclectic.net/tarot/cards/golden-dragon/
http://www.haunted.com.au/catalogue/tarot.html
http://www.thewitcheryonline.com/Tarot.htm
Love & Blessings
Milly
2007-07-24 23:54:55 · answer #1 · answered by milly_1963 7 · 0⤊ 0⤋
US Games Systems, Inc. is the largest publisher of tarot decks. They have available The Dragon Tarot deck and The Golden Dawn Tarot deck, but, sorry, they do not have The Golden Dragon Tarot. They don't have The Chinese Tarot Deck, but they do have the Feng Shui Tarot Deck (with Chinese artwork). They currently have 119 decks available--hopefully you can find one that resonates with you.
http://www.usgamesinc.com/search.php
If you are looking for a specific deck, try ebay. Good luck!
2007-07-25 00:46:04 · answer #2 · answered by lightningelemental 6 · 0⤊ 0⤋
The Golden Dragon deck is out of print so you may try some used book stores or ebay. Good luck!
2007-07-24 23:49:43 · answer #3 · answered by Lisa P 3 · 0⤊ 0⤋
All I can say is if you really want it you better grab it if you see it available because at what ever price you see it may be worth it. It's way too hard to fine. I only seen it in one or two of the links posted above and they were out-of-print.... Good Luck!!!
2007-07-25 02:18:51 · answer #4 · answered by Anonymous · 0⤊ 0⤋
http://www.aeclectic.net/tarot/cards/golden-dragon/
there's a buy link down the bottom
2007-07-24 23:39:34 · answer #5 · answered by crazy_one 4 · 0⤊ 0⤋
I have a copy that is available for sale We can talk.
2014-12-13 00:01:20 · answer #6 · answered by Alex 1 · 0⤊ 0⤋
nope dfont even know howto read cards!!!!
2007-07-25 03:57:17 · answer #7 · answered by Enrique C 2 · 0⤊ 0⤋