6.91 grams of N2, 4.71 grams of O2 and 2.95 G of He
Please show me how you did this as I did this and totaled up everything and my answer isn't jiving w/ the back of the book.
TY
2007-07-24 18:30:51 · 4 answers · asked by susanstudio2000 1 in Science & Mathematics ➔ Chemistry
(6.91g N2)*(1mol/28g N2) = 0.25 mol N2
(4.71gO2)*(1mol/32gO2)= 0.15 mol O2
(2.95g He)*(1mol/4g He) = 0.74 mol He
2007-07-24 18:38:47 · answer #1 · answered by Anonymous · 2⤊ 0⤋
6.91 grams of N2 X (6.02 X 10^23= 1 mol) / (N2=14.01 X 2 or 28.02 grams N2) so multiply 6.91 X 6.02 etc then divide by 28.02 try the others like this and see how you do.
2007-07-25 01:40:33 · answer #2 · answered by caseylynn0218 2 · 0⤊ 0⤋
Remember, N and O are dimers, so the mol wt of them are 28 and 32. The mol wt of He is 4. Now divide the grams by these mol weights to get moles.
2007-07-25 01:47:48 · answer #3 · answered by cattbarf 7 · 0⤊ 0⤋
total 14.57grams so easy
2007-07-25 01:39:25 · answer #4 · answered by Tan Boon Hwee k 2 · 0⤊ 2⤋