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In finding the distance between two points P1(x1,y1) and P2 (x2,y2), the most direct procedure is to use what formula?

2007-07-24 18:01:03 · 8 answers · asked by WiganRedskins 1 in Science & Mathematics Mathematics

8 answers

The distance formula:-
d² = (x2 - x1)² + (y2 - y1)²
Example
Points (3,4) and (6,8)
d² = (6 - 3)² + (8 - 4)²
d² = 9 + 16
d² = 25
d = 5

2007-07-24 19:31:37 · answer #1 · answered by Como 7 · 0 0

Use what is in effect a simple application of Pythagoras's Theorem:

d^2 = (x1 - x2)^2 + (y1 - y2)^2.

Therefore d = sqrt [(x1 - x2)^2 + (y1 - y2)^2],

i.e. d = [(x1 - x2)^2 + (y1 - y2)^2]^(1/2).

Live long and prosper.

P.S. Ah, Wigan, a great railway junction. More than 60 years later, in California, I can remember the cries I heard in my English boyhood: "Change at Wigan for Southport."

2007-07-24 18:04:18 · answer #2 · answered by Dr Spock 6 · 0 0

use the distance forumal the square root of (y1-y2)^2+(x1-x2)^2

2007-07-24 18:09:39 · answer #3 · answered by Tee-Tee 2 · 0 0

Pythagoreans theorm.
Square root of the sum of the squares of height and width.

For example,
If 3 high and 4 wide, then
the diagonal distance is
3 times 3 plus 4 times 4 which is
9 plus 16 is 25.
So 5 times 5 is 25, so answer is 5 distance.

2007-07-24 18:04:22 · answer #4 · answered by winter_new_hampshire 4 · 0 0

Use the pythagorean theorem, that is:

d^2 = {(x2)^2 - (x1)^2} + {(y2)^2 - (y1)^2}

where ^2 means raised to exponent of 2..♥..hope this helps!

2007-07-24 18:05:07 · answer #5 · answered by Anonymous · 0 0

d=sqroot of the sum of the quantity of the square of the head minus tail of 1 and 2

2007-07-24 18:21:35 · answer #6 · answered by Anonymous · 0 0

sqrt((x1-x2)^2 + (y1-y2)^2)

2007-07-24 18:04:12 · answer #7 · answered by unknown123 2 · 0 0

the distance formula.

it's pretty difficult to type the actual formula, but i'm sure if you google it you can find it!

Good luck!

2007-07-24 18:04:39 · answer #8 · answered by carolinegw09 2 · 0 0

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