The distance formula:-
d² = (x2 - x1)² + (y2 - y1)²
Example
Points (3,4) and (6,8)
d² = (6 - 3)² + (8 - 4)²
d² = 9 + 16
d² = 25
d = 5
2007-07-24 19:31:37
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answer #1
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answered by Como 7
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Use what is in effect a simple application of Pythagoras's Theorem:
d^2 = (x1 - x2)^2 + (y1 - y2)^2.
Therefore d = sqrt [(x1 - x2)^2 + (y1 - y2)^2],
i.e. d = [(x1 - x2)^2 + (y1 - y2)^2]^(1/2).
Live long and prosper.
P.S. Ah, Wigan, a great railway junction. More than 60 years later, in California, I can remember the cries I heard in my English boyhood: "Change at Wigan for Southport."
2007-07-24 18:04:18
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answer #2
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answered by Dr Spock 6
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use the distance forumal the square root of (y1-y2)^2+(x1-x2)^2
2007-07-24 18:09:39
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answer #3
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answered by Tee-Tee 2
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Pythagoreans theorm.
Square root of the sum of the squares of height and width.
For example,
If 3 high and 4 wide, then
the diagonal distance is
3 times 3 plus 4 times 4 which is
9 plus 16 is 25.
So 5 times 5 is 25, so answer is 5 distance.
2007-07-24 18:04:22
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answer #4
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answered by winter_new_hampshire 4
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Use the pythagorean theorem, that is:
d^2 = {(x2)^2 - (x1)^2} + {(y2)^2 - (y1)^2}
where ^2 means raised to exponent of 2..â¥..hope this helps!
2007-07-24 18:05:07
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answer #5
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answered by Anonymous
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d=sqroot of the sum of the quantity of the square of the head minus tail of 1 and 2
2007-07-24 18:21:35
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answer #6
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answered by Anonymous
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sqrt((x1-x2)^2 + (y1-y2)^2)
2007-07-24 18:04:12
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answer #7
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answered by unknown123 2
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the distance formula.
it's pretty difficult to type the actual formula, but i'm sure if you google it you can find it!
Good luck!
2007-07-24 18:04:39
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answer #8
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answered by carolinegw09 2
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