lim as x approaches infinity
e^-x*cosx
please explain
2007-07-24 16:42:15 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
e^1/(xcosx)
1/infinity=0
e^0=1
2007-07-24 16:46:55 · answer #1 · answered by iyiogrenci 6 · 0⤊ 0⤋
It's hard to figure out how to interpret your expression. The value e^(-xcosx) has no limit because xcosx does not approach any value. The value (e^-x)cosx approaches 0 because e^-x approaches 0.
2007-07-24 16:54:52 · answer #2 · answered by John B 6 · 0⤊ 0⤋
lim e^x*cosx
x- infinity
= e^infinity = infinity
[ because x*cosx approaches infinity as x appro... infinity]
2007-07-24 16:51:52 · answer #3 · answered by vicky 7 2 · 0⤊ 0⤋
there is no limit.
2007-07-24 16:49:49 · answer #4 · answered by climberguy12 7 · 0⤊ 0⤋