no clue how to do this related rates problem...?

Question

Water is leaking out of an inverted conical tank at a rate of 11000 cm^3/min at the same time that water is being pumped into the tank at a constant rate. The tank has height 6 m and the diameter at the top is 4 m. If the water level is rising at a rate of 20 cm/min when the height of the water is 2 m, find the rate at which water is being pumped into the tank.

Answer 1

V = (π/3)hr^2
r/h = R/H
V = (π/3)Hh^3/R
dV/dt = (πHh^2/R)dh/dt = Q(in) - Q(out)
Q(in) = Q(out) - (πHh^2/R)dh/dt
Q(in) = 11,000 - π(600)(200^2)(- 20)/(200)
Q(in) ≈ 11,000 + 7,539,822
Q(in) ≈ 7,550,822 cm^3/min = 7,550.822 L/min

Answer 2

You will first need to find the volume of the conical flask and for that you need the diameter of the top of the flask (Which is 4m) and that of the bottom which is not stated. To solve this one you will need the diameter of the bottom of the flask, at least thats what I think. Sorry I couldn't be of much help.