Need help solving the indicated operations
2√[48] + 7√[12] –√[27]
2007-07-24 12:42:48 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
48 = 16 * 3
12 = 4 * 3
27 = 9 * 3
Thus we can write the expression as:
2 root(16*3) + 7 root(4 * 3) - root(9 * 3)
= 2*4 root(3) + 7 *2 root(3) - 3 root(3)
= (8 + 14 - 3) * root(3)
= 19 * root(3)
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2007-07-24 12:47:07 · answer #1 · answered by G M 2 · 0⤊ 0⤋
2â48 + 7â12 - â27 =
2â(16•3) + 7â(4•3) - â(9•3) =
2•4â3 + 7•2â3 - 3â3 =
8â3 + 14â3 - 3â3 =
19â3
2007-07-24 19:47:56 · answer #2 · answered by Philo 7 · 0⤊ 0⤋
2â[48] + 7â[12] –â[27]
= 2â(4*4*3) + 7â(4*3) - â(9*3)
= 2*2*2â3 + 7*2â3 - 3â3
= 8â3 + 14â3 - 3â3
= 19â3
2007-07-24 19:50:05 · answer #3 · answered by fofo m 3 · 0⤊ 0⤋
simpified:
2â3â16 + 7â3â4 - â3â9
2*4*â3 + 7*2*â3 - 3*â3
8â3 + 14â3 - 3â3
19â3
solved:
32.90896534
2007-07-24 19:50:30 · answer #4 · answered by Lin 2 · 0⤊ 0⤋
2â[2^4x3] + 7â[2^2x3] –â[3^3]
8â3 + 14â3 – 3â3
19â3
2007-07-24 19:53:31 · answer #5 · answered by Anonymous · 0⤊ 0⤋
2(rt48) =2(rt16)(rt3), =(2)(4)(rt3)=8(rt3)
7(rt12) =7(rt4)(rt3), =(7)(2)(rt3) =14(rt3)
(rt27) = (rt9)(rt3) =3(rt3)
Therefore 2(rt48) + 7(rt12) -(rt27)=8(rt3)+14(rt3)-3(rt3)
=19(rt3)
2007-07-24 19:54:14 · answer #6 · answered by Grampedo 7 · 0⤊ 0⤋