how do I solve 6x^2+42x=0?

Question

by factoring

Answer 1

6x (x + 7) = 0
x = 0 , x = - 7

Answer 2

6x^2 + 42x = 0
Take out a common 6x term:
6x(x + 7) = 0

6x = 0
Divide both sides by 6:
x = 0

x+7=0
Subtract 7 from both sides:
x = -7

Check answers:
Check 0:
6(0^2) + 42(0) = 0
0 = 0

Check -7:
6((-7)^2) + 42(-7) = 0
6(49) + -7(42) = 0
294 - 294 = 0
0 = 0

Both answers check.
So x = 0 or -7

Answer 3

Hey there!

Here's the answer.

6x^2+42x=0 --> Write the problem.
6x(x+7)=0 --> Factor out the 6x.
6x=0 or x+7=0 --> Use the zero-product property i.e. if pq=0, then p=0 or q=0.
x=0 or x=-7 --> Solve each equation for x.
{-7,0} Write the solutions in the set.

So the answer is x=0 or x=-7, or {-7,0}.

Hope it helps!

Answer 4

6x²+42x=0
Factorise,
6x(x+7)=0
When the product of two numbers is equal to zero, one of the numbers must be zero.
Let 6x=0
x=0/6=0
or
Let(x+7)=0
x=-7
The possible values of x,are "0" or "-7".....Ans.
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Verification:
Substitute"0" in the given equation,
6(0)²+42(0)=0
Substitute"-7" in the given equation,
6(-7)²+42(-7)=6*49-42*7=294-294=0

Answer 5

6x^2+42x=0
or 6x(x+7)=0
so Either 6x=0 or x+7=0
so x=0 or x=-7 ans

Answer 6

First, you can divide both sides by 6 and you get:

x^2 + 7x = 0

Then, you can factor out an x on the left hand side of the equation:

x(x + 7) = 0

So, you have two possible solutions:

x = 0 or
x+7 = 0 ------>x = -7

So, x = 0 or -7

Answer 7

6x(x+7)=0

x=0, -7