Factor the polynomial completely. If the polynomial cannot be factored, write prime.
24k^3m - 81m^4
(6km - 9m^2)(4k^2 + 9m^2)
3m(2k - 3m)(4k^2 + 6km + 9m^2)
3m(8k - 3m)(k^2 + 6km + 9m^2)
3m(2k + 3m^2)(4k^2 - 6km + 9km^2)
2007-07-24 10:56:07 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
24mk^3 - 81m^4
First take out a common 3m:
3m(8k^3 - 27m^3)
Now use difference of cubes to factor:
Difference of cubes:
a^3 - b^3 = (a - b)(a^2 + ab + b^2)
In your case, a=2k and b=3m
3m[(2k - 3m)((2k)^2 + (2k)(3m) + (3m)^2)]
= 3m(2k - 3m)(4k^2 + 6km + 9km^2)
2007-07-24 11:00:55 · answer #1 · answered by whitesox09 7 · 0⤊ 0⤋
24k^3m - 81m^4
= 3m(8k^3 -27m^3)
= 3m (2k-3m)(4k^2+6km +9m^2)
2007-07-24 18:04:10 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
24k^3m - 81m^4
= 3m (8k^3 - 27m^3)
2007-07-24 18:02:06 · answer #3 · answered by Anonymous · 0⤊ 1⤋
b
2007-07-24 18:03:50 · answer #4 · answered by Kenneth H 3 · 0⤊ 0⤋