Ok did this problem and wonder if got answer right?

Question

I did this polynomial or whatever it is and wonder if the answer I got is right

(-2y) (3x square + 3y - 1)

I got for the answer -6y+3x square - 1.

Now I get what to do. Your distrubuting the 3 to the negative two to make it 3 times negative 2 which equals 6 and you add the y and the x and the square understand now.

Answer 1

Hi,

-2y(3x² + 3y - 1) = -6x²y - 6y² + 2y

That's it !!!

I hope that helps!! :-)

Answer 2

No, sorry. You need to distribute the multiplication by -2y across all three terms of the second polynomial. You should get -6(x^2)y - 6y^2 + 2y. Look at the terms separately:

-2y*3x^2 = -6(x^2)y
-2y*3y = -6y^2
-2y*(-1) = 2y

Answer 3

It should be

-2y * 3x^2 - 2y * 3y - 2y * (-1)

-6x^2y - 6y^2 + 2y

-6 y square - 6 x square y + 2y

Answer 4

(-2y)(3x^2 + 3y - 1)
-6yx^2 - 6y^2 + 2y
y(-6x^2 - 6y + 2)
And that's as far as you can go
You can't solve an equation with two variables, you need two equations or one equality.

Answer 5

you must multiply each term in the second expression by the first term. -2y*3x**2 + (-2y)*3y - (-2y)*(1)

you get: -6yx**2 - 6y**2 + 2y

Answer 6

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Answer 7

-6yx^2 -6y^2+2y

or in your notation:

-6y xsquared - 6 ysquared + 2y