1. Simplify the square root 6x^2?

Question

2. Simplify: square root 27 - square root 3?

I got 2 square root 3x for the first one and 9 square root 3 on the second one. Is this right?

Answer 1

#1. The way you have it written there, it would simplify to x sqrt(6)
#2. sqrt (27) is equal to 3 * sqrt(3), so you have 3 * sqrt(3) - 1 * sqrt(3) = 2 * sqrt(3)

A good way to start with simplifying roots, is to reduce the number inside the root to prime numbers, so for #1, you would get sqrt(x*x*3*2). The next thing to do is group pairs of terms and put one outside, so you get x * sqrt(3*2), when there are no pairs left inside, you can do the multiplication, and you get x * sqrt (6).

For the second one, sqrt(27) reduces to sqrt(3*3*3), so you can pair two of those 3's, and move one outside the sqrt, and leave 3 * sqrt(3).

Answer 2

a million: Multiply the two roots. answer is Sqrt 12, or (sqrt 4)(Sqrt 3) = 2(Sqrt 3) #2. Multiply total quantity with the help of total quantity, root with the help of root. the respond is 14(sqrt seventy 5), which equals 14(Sqrt 25)(Sqrt 3) = (14)(5)(Sqrt 3) = 70(Sqrt 3) i wish this facilitates.

Answer 3

1. Answer for the first one is x * square root(6) where * is the multiplication sign.

2. Answer is 3sqrt(3) - sqrt(3) = 2sqrt(3)

Answer 4

square root cancel out with the power^2 which is equal 6x

Answer 5

1.
sqrt(6x^2)
= sqrt(6)sqrt(x^2)
= x sqrt(6).

2.
sqrt(27) - sqrt(3)
= sqrt(9)sqrt(3) - sqrt(3)
Factorise out the sqrt(3):
sqrt(3)(sqrt(9) - 1)
= sqrt(3)(3 - 1)
= 2sqrt(3).

No, sorry. You are wrong.

Answer 6

1. Ans. 2 root 3x
2. Ans. 5.196

Answer 7

sqrt(6x^2)= IxI*sqrt6 because x can be positive or negative so you need abs val.

Answer 8

sqrt6x^2 is (x)sqrt6 or (x)sqrt2sqrt3

sqrt27 is 3sqrt3 - sqrt2 = 2sqrt3