2007-07-24 07:22:17 · 6 answers · asked by Marilyn C 1 in Education & Reference ➔ Homework Help
ok
1. this thing is awesome
i didnt think id get answers so quickly
2. the actual problem is :
(3p-1)(9p^2+3p+1)
i wasnt exactly sure how to solve it so i thought id reverse foil the second part and then do this whole complicated thing and
yea ok i know
i was wrong : )
but uhm i guess i should have asked the entire question
anyway
if one of you geniouses out there can solve it
i shall be eternally grateful : )
3. THANKS!!
2007-07-24 07:49:04 · update #1
(3p-1)(9p^2+3p+1) =
27p^3 + 9p^2 + 3p
............- 9p^2 - 3p - 1 =
27p^3 - 1
2007-07-24 08:51:18 · answer #1 · answered by Steve A 7 · 0⤊ 0⤋
(9p^2 + 3p + 1) ... you can't use FOIL... you have to use the quadratic equation to find the roots p
It's not (3p + 1)(3p + 1) because that would result in
3p^2 + 6p + 1
The only other option is (9p + 1)(p+1)... but that is not right either because that gives you 9p^2 + 10p + 1...
You have to use the quadratic equation...
Did you mean 9p^2 + 6p + 1... and you just had a slip of the finger typing 3p instead of 6p?
2007-07-24 14:31:23 · answer #2 · answered by blueskies 7 · 0⤊ 0⤋
(3p+1)(3p+1) is what im thinking but that won't work cause you would get (9p^2+6p+1) Did you copy it wrong...cause what you have can't actually be foiled.
2007-07-24 14:30:45 · answer #3 · answered by Chris G 2 · 0⤊ 0⤋
[3p+1][3p+1] expands to 9p^2+6p+1 !!!!!!!!!!!!!!!!
Marilyn, have you got the question down correctly ?
2007-07-24 14:36:15 · answer #4 · answered by Twiggy 7 · 0⤊ 0⤋
In this equation the answer is:
No Real Roots.
This problem is not factorable.
2007-07-24 14:37:14 · answer #5 · answered by sportsoser 3 · 1⤊ 0⤋
what is the original question? Because it doesn't seem right that you would have to FOIL that problem.
2007-07-24 15:57:18 · answer #6 · answered by Mahina 2 · 0⤊ 0⤋