2007-07-24 06:43:24 · 3 answers · asked by mramahmedmram 3 in Science & Mathematics ➔ Mathematics
I presume you want to know the volume of the water remaining in the box.
The diameter of the sphere is 20 cm, which makes it just big enough to fit into the box. However, the sphere exceeds the box in height. Only 5 cm of the sphere is immersed.
Volume of the parallelopiped Vp = 20x20x5 = 2000 cm^3
Volume of sphere immersed in water Vs = 654.5 cm^3
The calculation of the volume of the sphere immersed in the water is a bit complicated. I can explain that personally, but it requires the user to understand integration.
Hence, volume of water left in box Vw= Vp - Vs = 1345.5 cm^3
2007-07-24 07:21:34 · answer #1 · answered by locutus83 2 · 0⤊ 0⤋
Volome of the Pipe=Base x Height
=(20 x 20) x 5=2000 cu cm
Volume of the sphere= Pi x r^2
= 3.14 x 10^2
=314 cu cm
so the rest water=2000-314=1686 cu cm ans
2007-07-24 14:06:43 · answer #2 · answered by MAHAANIM07 4 · 0⤊ 0⤋
Vp = 20^2*5 = 2000
Vs = Pi*10^2 = 100Pi
VH2O = 2000 - 100Pi
2007-07-24 13:47:50 · answer #3 · answered by gebobs 6 · 0⤊ 0⤋