if i'm trying to hit a target with a rifle that is 1.5 miles away and my round travels at 1200 meters per sec.

Question

how long will it take for my bullet to hit the target?

Answer 1

Velocity = distance/time

Time = distance/velocity

Distance = 1.5 miles = 2414 meters

2414 metes/1200 (m/s) = 2.01 seconds

Answer 2

The bullit-path describes a "flat curve", u aim with an
angel above horizon, from start u don't know what angel
but adjust according to result from target.

there are formulas for this, dynamics...; however considering drag, airpressure etc.. there is a resolution BUT u must
simulate the situation using programs as Maple and u will
get an answer with good accuracy. The drag at this velocity
is considerable and will lessen some at the end of the path,
as the bullit travels with a lesser velocity.

I mean there is no easy way to solve thy ballistic problem in
order to get a fairly realistic answer because the bullit-path
does NOT describe a straight line. So I dare say it will take
a little more time to hit the target compared to what all
dudes say using linear analyses. To their honor I guess
they are within 10 % from real answer and thats good.
(however their bullits will probably not reach the target, in
best case go under it :)

Answer 3

2430 m = 1 . 5 miles
t = distance / speed
t = 2430 / 1200 sec
t = 243 / 120 sec
t = 81 / 40 sec
t = 2 . 025 sec

Answer 4

Assuming you are not counting wind resistance or gravity's influence on the bullet and assuming that it is a perfect shot, it is a pretty simple D = TR problem (distance = time * resistance).

1.5 mi = 2430 meters
So that's the distance.

2430m = 1200m/sec * t
t = 2430m/(1200m/sec)=2.025 seconds

So there's your answer. 2.025 secs

Answer 5

1.5 mile=2413.904088 meter
so 2414/1200 (m/s)= 2.011667 seconds

Answer 6

1.5 miles = 2,414.016 meters

2,414.016 / 1,200 = 2.01168

Answer: 2.01168 seconds

Answer 7

2 seconds: 1.5/(1.2/1.6)