I will put this with each of my questions today, I am out of school, I am trying to re-teach myself algebra which is a little difficult when you haven't done it in some time, so as I work through a problem I use yahoo answers to check it to see if I did it correctly. thank you for all your help :)
Write an equation in slope-intercept form of a line with the following characteristics: parallel to the graph of:
-4x + 3y = 12 and passes through the orgin.
2007-07-24 04:06:22 · 3 answers · asked by Amber B 1 in Science & Mathematics ➔ Mathematics
Start by rewriting the given equation in slope-intercept form, which is y = mx + b where m is slope and b is the y-intercept (the value of y when x = 0).
-4x + 3y = 12
3y = 4x + 12
y = (4/3)x + 4
So the slope of the given line is 4/3, and the new line must have the same slope in order to be parallel. The origin is (0, 0), so the requested line has a y-intercept of 0. The line is therefore y = (4/3)x.
2007-07-24 04:09:25 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
Hello again!
Re-write -4x +3y = 12 into standard form. That requires you to get +1y all by itself.
3y = 4x + 12
y = (4/3)x + 12/3, y = (4/3)x + 4
The line you seek is parallel to this and therefore has the same slope, namely 4/3. So the required eq'n has
this form: y = (4/3)x + b.
Since the line passes through (0,0) i,e. the origin, we substitute 0 for x, 0for y, to find b. And we get b=0
Your required eq'n is y=(4/3)x
2007-07-24 11:59:15 · answer #2 · answered by Grampedo 7 · 0⤊ 0⤋
the origin is another way of saying the point (0,0) so you want to find the slope of that line and not put an intercept on the end of the equation so it passes through the point (0,0)
-4x + 3y = 12
3y = 12 + 4x
y = 4 + 4/3x
y = mx + b
so m = 4/3
so now to be parallel they must have the same slop but it must also pass through the origin (0,0). so your new equation is
y = 4/3x
because when x=0 y also =0
2007-07-24 11:12:49 · answer #3 · answered by Event Horizon 2 · 0⤊ 0⤋