I will put this with each of my questions today, I am out of school, I am trying to re-teach myself algebra which is a little difficult when you haven't done it in some time, so as I work through a problem I use yahoo answers to check it to see if I did it correctly. thank you for all your help :)
Determine the y-intercept of the graph: -3x-5y =15
2007-07-24 03:59:13 · 5 answers · asked by Amber B 1 in Science & Mathematics ➔ Mathematics
If you put any linear(meaning straight line) equation into standard form, y = mx + b, then the y-intercept is whatever b is.
-3x -5y = 15 in standard form becomes -5y = 3x + 15' which then becomes 5y = -3x -15, and finally
y = (-3/5)x -3
Answer: the y-intercept is -3, or more properly (0,-3)
2007-07-24 05:06:02 · answer #1 · answered by Grampedo 7 · 0⤊ 0⤋
-3x-5y =15 - Put this into slope intercept form which is y=mx+b
-5y=3x+15 <--thats in slope intercept form; then divide by -5
since you want to get y alone. So now you have:
y=-3/5x-3
The y intercept would be -3
2007-07-24 11:08:03 · answer #2 · answered by _~^*^~_ Ninja Fighter_~^*^~_ 4 · 0⤊ 0⤋
write in form y=ax+b
then -5y= 15+3x
y= -3 -3/5 xand for x=0 you have intercept axis
so y =-3
2007-07-24 11:11:52 · answer #3 · answered by maussy 7 · 0⤊ 0⤋
5y = - 3x - 15
When x = 0 , y = - 3 which is y intercept.
2007-07-24 11:29:19 · answer #4 · answered by Como 7 · 0⤊ 0⤋
its (0,-3)
2007-07-24 11:37:54 · answer #5 · answered by dory122003 1 · 0⤊ 0⤋