3(2x+4)-8x < 14?

3(2x+4) - 8x < 14
First distribute the 3 through the parentheses.
6x + 12 - 8x < 14
Combine the 6x and -8x
-2x + 12 < 14
Subtract 12 from each side
-2x < 2
Divide both sides by -2 (remember to flip the inequality sign when dividing by a negative number).
x > -1

2007-07-24 03:51:52 · answer #1 · answered by MsMath 7 · 1⤊ 0⤋

Hey there!

Here's the answer.

3(2x+4)-8x<14 --> Write the problem.
6x+12-8x<14 --> Distribute 3 into 2x+4.
6x-8x+12<14 --> Gather the x terms together and the constant together.
-2x+12<14 --> Add 6x and -8x.
-2x<2 --> Subtract 12 on both sides of the equation.
2x>-2 --> Divide both sides by -1 and reverse the inequality sign.
x>-1 Divide both sides by 2.

So the answer is x>-1 or -1
Hope it helps!

2007-07-24 10:56:56 · answer #2 · answered by ? 6 · 1⤊ 0⤋

3(2x+4) - 8x < 14
First distribute the 3 through the parentheses.
6x + 12 - 8x < 14
Combine the 6x and -8x
-2x + 12 < 14
Subtract 12 from each side
-2x < 2
Divide both sides by -2 (remember to flip the inequality sign when dividing by a negative number).
x > -1

2007-07-24 10:56:46 · answer #3 · answered by karyn_colton 1 · 1⤊ 0⤋

3(2X+4)-8X < 14 then multiply out the 3
6X + 12 - 8x <14 then group like terms
-2x < 2 then divide out the -2
X < -2

2007-07-24 10:54:31 · answer #4 · answered by Les 2 · 0⤊ 1⤋

6x + 12 -8x < 14
-2x + 12 < 14
-2x < 2
2x > -2
x > -1

2007-07-24 10:53:49 · answer #5 · answered by essebful 2 · 1⤊ 0⤋

6x + 12 - 8x < 14
- 2x < 2
2x > - 2
x > - 1

2007-07-26 17:39:03 · answer #6 · answered by Como 7 · 0⤊ 0⤋

develop left side

6x+12-8x<14
-2x<2
-x<1
x>-1

2007-07-24 10:55:43 · answer #7 · answered by maussy 7 · 1⤊ 0⤋

factor first:

6x + 12 - 8x < 14

combine like terms:

-2x < 2

divide by 2:

-x < 1

or it can be written:

x > -1

2007-07-24 10:52:14 · answer #8 · answered by miggitymaggz 5 · 1⤊ 0⤋

8 answers