Determine the x-intercept of the graph: 2x+4y+8.
2007-07-24 03:16:38 · 9 answers · asked by Jamie W 1 in Science & Mathematics ➔ Mathematics
I assume you meant
2x + 4y = 8 (not +8)
The x-intercept is when y = 0.
So...
2x + 4(0) = 8
2x = 8
x = 4
So the x-intercept is 4, or (4, 0).
2007-07-24 03:19:14 · answer #1 · answered by Mathematica 7 · 3⤊ 2⤋
You must mean 2x+4y = 8. If so, then simply set y=0 and solve for x.
This gives 2x = 8
x= 4
The x-intercept is (4,0)
2007-07-24 10:23:52 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
2x+4y+8=what to solve
2007-07-24 10:43:03 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The x intercept is the point at which the line crosses the x-axis and y = 0
Set y to zero in the equation and solve for x.
2007-07-24 10:21:51 · answer #4 · answered by kindricko 7 · 0⤊ 0⤋
2x + 4y + 8 = 0
when y = 0
2x = - 8
x = - 4
2007-07-24 10:21:44 · answer #5 · answered by CPUcate 6 · 0⤊ 0⤋
The line intercepts the X-axis where Y=0.
Now do your homework.
2007-07-24 10:19:30 · answer #6 · answered by Dr 8'lls 4 · 1⤊ 1⤋
you can get the x-int when you set y=0
so
2x + 4(0) + 8 = 0
transpose 8 to the other side... (rem. to change the sign after you transpose it...) or just subtract 8 on both sides
so you'll get
2x = -8
x=-4
2007-07-24 10:24:23 · answer #7 · answered by >_< 2 · 0⤊ 0⤋
the answer is 2x+4y+8
there are no like values such as x y and 8
2007-07-24 10:19:37 · answer #8 · answered by Anonymous · 0⤊ 3⤋
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2007-07-24 10:18:23 · answer #9 · answered by Anonymous · 0⤊ 5⤋