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just curious.

2007-07-24 00:27:52 · 12 answers · asked by edwin l 1 in Science & Mathematics Mathematics

sorry,say you pick six numbers;i,e 2,23,30,33.45,47.these numbers don,t contain consecutive numbers_;i,e 4,5,15,20,32,41,these do(4,5)so i would like to know how many non consecutive number combinations there are( is this less confusing)

2007-07-26 11:20:53 · update #1

12 answers

If you mean that those are the numbers you won't enter on your lottery slip, the odds are still 13983816 to 1.

2007-07-24 00:38:49 · answer #1 · answered by Polo 7 · 0 1

I think the answer is 7,059,052.

If you play with writing out all the possible sequences for small versions of the problem (e.g. choosing 3 from 8 numbers, etc.) you will see the patterns developing.

If I understand you correctly, you want the number of ways to choose six numbers from 49 such that no two numbers are consecutive. The order does not matter.

It is well known that the odds of choosing any six numbers from 49 is (49 choose 6) which equals 13,983,816.

Eliminating consecutive numbers means that there must be five numbers that cannot be selected in every choice since there are 5 spaces between six items. So the problem translates to the equivalent of choosing 6 numbers from 44.

(44 choose 6) is the answer above.

So about half the normal lottery selections have a pair of consecutive numbers.

Edit: I wondered if I had that right so have just been to check the actual results of the main draw from February to June 2007 on the National Lottery website. There were 43 draws in that period so we would expect the number of sequences without any consecutive numbers to be 22. There were actually 24 which I think is pretty close for such a small sample.

2007-07-28 05:19:35 · answer #2 · answered by tringyokel 6 · 1 0

you mean if no consecutive numbers came out in any draw would the combinations, therefore the odds be reduced to win i think. still don,t know.

2007-07-24 08:13:21 · answer #3 · answered by sophie l 2 · 0 0

Not sure what you mean but the numbers are purely random so it doesn't matter what you do there is an equal chance of any 6 numbers coming up.

2007-07-25 04:21:36 · answer #4 · answered by brainyandy 6 · 0 0

What do you mean? The chances of any combination of numbers coming up (regardless of whether they run consecutively or not) is EXACTLY THE SAME as any other combination.

2007-07-24 07:36:05 · answer #5 · answered by eriverpipe 7 · 1 1

Are you saying , what are the odds where a number is chosen and NOT replaced. For example if number 7 is chosen, the 7 ball stays out and there is one less ball to choose from?

Clarify your question and I will answer it.

2007-07-24 07:37:53 · answer #6 · answered by Anonymous · 0 2

If the numbers 1,2,3,4,5,6 came out it would still be the same odds as any other win... around 14 million to one..

2007-07-24 16:58:27 · answer #7 · answered by Anonymous · 0 0

the odds are as much as you were to be struck by lightning while outside waiting for a meteor to hit you

2007-07-24 07:35:41 · answer #8 · answered by Anonymous · 0 1

not very much

2007-07-25 10:31:29 · answer #9 · answered by Anonymous · 0 0

1 in 1????????????????????????????????????????????????????????????????????????????????????????????????????????????????.

2007-07-30 23:03:05 · answer #10 · answered by Anonymous · 0 0

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