At a school play, adults were charged 75c and students 25c to get in and $330 was collected in total receipts. The play was held in a 600 seat auditorium which was not filled. The minimum number of adults at the play was:
a 359
b 300
c 365
d 361
e 367
2007-07-23 22:08:25 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
How can you find out the answer?
2007-07-23 22:19:27 · update #1
How do you get 361 in the 1st place?
Amount collected from adults = 361(0.75) = 270.75
2007-07-23 22:38:29 · update #2
(d) 361
Amount collected from adults = 361(0.75) = 270.75
Amount collected from students = 330 - 269.25 = $59.25
Therefore, no of students = 59.25/0.25 = 237
Total no of people there = 361 + 237 = 598
2007-07-23 22:15:19 · answer #1 · answered by cherrypassion 2 · 0⤊ 0⤋
0.75a + 0.25c = 330
a + c < 600
75a + 25c = 33,000
3a + c = 1,320
c = 1,320 - 3a
a + 1,320 - 3a < 600
720 - 2a < 0
2a > 720
a > 360
a ⥠361
c = (330.00 - 0.75*361)/0.25
c = 237
a + c = 598
if a = 360
c = (330.00 - 0.75*360)/0.25 = 240
360 + 240 = 600, but 600 seats were not all filled.
2007-07-23 22:39:50 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
Well lilee if they all were adults, it would be 440. That ain't one of the choices, however. Pick, the highest number, if your taking a test. That would be 367. (e.)
2007-07-23 22:31:36 · answer #3 · answered by JIMMY 3 · 0⤊ 0⤋
(a) 359.
Solve the simultaneous eqn:
x + y < 600
0.75x + 0.25y = 330
you'll get x < 360. which means 359.
2007-07-23 22:29:04 · answer #4 · answered by art70123 1 · 0⤊ 1⤋