2007-07-23 22:00:39 · 7 answers · asked by ashok v 1 in Science & Mathematics ➔ Mathematics
Get the answer by log
since A^3/2
Let A^3/2=v
Taking log
logA^3/2=log v
3/2*log A=Log v
By getting the values from log table u will get
Value=log V
therefore antilog v =value of A^3/2
2007-07-24 00:32:02 · answer #1 · answered by Nikhil B 2 · 0⤊ 0⤋
Multiply A with the square root of A
ie., A*A^1/2=A^(1+1/2)=A^3/2.
2007-07-24 12:55:46 · answer #2 · answered by Anonymous · 0⤊ 0⤋
A^3/2 =square root of cube of A
2007-07-24 05:04:35 · answer #3 · answered by maussy 7 · 0⤊ 0⤋
Let A^3/2=v
Taking log
logA^3/2=log v
3/2*log A=Log v
By getting the values from log table u will get
Value=log V
therefore antilog v =value of A^3/2
2007-07-24 08:03:04 · answer #4 · answered by kaushik patel 2 · 0⤊ 0⤋
Square root the value of A and then raise the result to power 3.
2007-07-24 05:03:56 · answer #5 · answered by Anonymous · 0⤊ 0⤋
find the cube of A then take square root of it.
A^3/2 = (A^3)^1/2 = sqrt(A^3)
2007-07-24 05:04:37 · answer #6 · answered by Jain 4 · 0⤊ 0⤋
first find the root of A.then find the cube of it,
2007-07-25 05:09:37 · answer #7 · answered by MathStudent 3 · 0⤊ 0⤋