Simplifying:when x is equal to -3 and y to +5...how do you solve (x+3y)to the second power?

Question

I don't know how to solve this problem...Thanks for the help!

Answer 1

put x=-3 & y=5 in (x+3y) to the power 2

(-3+3*5) to the power 2
=(-3+15) to the power 2
=(12) to the power 2
=12*12
=144

Answer 2

Ans:
=(x+3y)^2
=[-3+3(5)]^2
=(-3+15)^2
=12^2
=144

Answer 3

You are probably asking the solution to (x + 3y)^2.

Since you are given the values of x and y solve the terms within the brackets first.

So, (x + 3y)^2 = (-3 + 3(5))^2 = (-3 + 15)^2 = (12)^2 = 144.

Another way of doing this is expanding (x + 3y)^2.

General formula is: (a + b)^2 = a^2 + 2ab + b^2.

In our problem, a = x and b = 3y.

Applying the formula (x + 3y)^2 becomes:
x^2 + 2(x)(3y) + (3y)^2 = x^2 + 6xy + 9y^2

Now substitute the values of x and y.
x^2 + 6xy + 9y^2 = (-3)^2 + 6(-3)(5) + 9(5)^2 = 9 - 90 + 225 = 144

Answer 4

put x=-3 & y=5 in (x+3y) to the power 2

(-3+3*5) to the power 2
=(-3+15) to the power 2
=(12) to the power 2
=12*12
=144

Answer 5

x = -3
y = 5

(-3 + 3*5)^2 [substitute the values for the variables]

(-3 + 15)^2 [multiply the 3 and 5 together]

12^2 [Add the -3 and 15 together]

12^2 = 12*12 = 144 [multiply 12 times 12]

Answer 6

(-3+15)²=0 <---is this what you mean?
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put x=-3 & y=5 in (x+3y) to the power 2

(-3+3*5) to the power 2
=(-3+15) to the power 2
=(12) to the power 2
=12*12
=144
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x = -3
y = 5

(-3 + 3*5)^2 [substitute the values for the variables]

(-3 + 15)^2 [multiply the 3 and 5 together]

12^2 [Add the -3 and 15 together]

12^2 = 12*12 = 144 [multiply 12 times 12]
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You are probably asking the solution to (x + 3y)^2.

Since you are given the values of x and y solve the terms within the brackets first.

So, (x + 3y)^2 = (-3 + 3(5))^2 = (-3 + 15)^2 = (12)^2 = 144.

Another way of doing this is expanding (x + 3y)^2.

General formula is: (a + b)^2 = a^2 + 2ab + b^2.

In our problem, a = x and b = 3y.

Applying the formula (x + 3y)^2 becomes:
x^2 + 2(x)(3y) + (3y)^2 = x^2 + 6xy + 9y^2

Now substitute the values of x and y.
x^2 + 6xy + 9y^2 = (-3)^2 + 6(-3)(5) + 9(5)^2 = 9 - 90 + 225 = 144
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Answer 7

(- 3 + 15)² = 12² = 144

Answer 8

just substitute it..so you can now have:
= [-3+(3*5)]to the second power
= [-3+15] to the second power
= 12 to the second power..
so the final answer is 144.

Answer 9

hmmm...
it's easy...
first you must substitute all the given in the equation like x=-3 and y=5 so, (x+3y)to the 2nd power [-2+3(5)]^2
(-2+15)^2 (13)^2 then, multiply 13 by itself just like this
13 x 13 to get the answer of 169...

Answer 10

(-3+15)²=0 <---is this what you mean?