three cards are drawn from a deck...what is the probability that u the second card is an ace without the first being showed to u
2007-07-23 19:13:03 · 5 answers · asked by ellie_2121 3 in Science & Mathematics ➔ Mathematics
i got 16/132600
2007-07-23 19:16:59 · update #1
The first can be an ace or not:
If it is an ace, the probability that the second is also an ace is:
4/52*3/51
If the first is not ace, the second is an ace:
48/52*4/51
Add the two: 4/52*3/51 + 48/52*4/51 = 204/2652
= 1/13 still. d:
2007-07-23 19:22:55 · answer #1 · answered by Alam Ko Iyan 7 · 1⤊ 0⤋
the probability of the 1st card being an ace is 4/52=1/13
if the first is an ace then the 2nd has a 3/51 of being an ace if not then 4/51 is the likely hood of card 2 being an ace.
2007-07-23 20:17:40 · answer #2 · answered by 037 G 6 · 0⤊ 0⤋
4/52. = 1/13.
if the first one is not shown to you, it might as well have not been drawn.
2007-07-23 19:22:20 · answer #3 · answered by Anonymous · 0⤊ 0⤋
not sure the first but the second one i know. you have a 1/2 chance of each one. so you do 1/2 x 1/2 x 1/2 so 1/8 that you guess all three correctly
2016-04-01 10:20:21 · answer #4 · answered by Maria 4 · 0⤊ 0⤋
no actually its 1/13
2007-07-23 19:21:22 · answer #5 · answered by Timmy 3 · 0⤊ 0⤋