Physics question?

Question

If an object is moving at 4.3m/s^2, how far will it travel in 10sec?

The answer is 215m. I want to know the steps to this solution please.

Answer 1

a = 4.3m/s^2
t = 10 sec
d = ?

given d = (v inital)*t + 1/2a * t^2
but if velocity initial =0m/s
then d = 1/2(4.3 m/s^2)(10 s)^2
= 1/2(4.3 m)(100)
= 1/2(430m)
= 215 m

Answer 2

s = ut + 1/2 a.t^2 is the equation to be used. Here we are given the acceleration as 4.3 m/sec^2 but we don't have the initial velocity and so assume it as zero.

s = 0 + 4.3 / 2 x 10 x 10 = 430 / 2 = 215 m

Answer 3

that problem is impossible without knowing either initial velocity or final velocity. from the answer of 215, i can derive that the initial velocity is zero.

the book may have left it out accidentally.

formula:
d = 1/2at^2 +(Vi)t

d = 1/2(4.3)(10^2) +(0)(10)
d = 1/2(430) + 0
d=215

Answer 4

♦ s = 0.5a*t^2; s= 0.5*4.3*10^2 =215 m;