Find the area of a rhombus whose perimeter is 52 and the longer diagonal is 24 !!?

Answer 1

First, think what you know.
1) Because the perimiter is 52, each side is 13. We know this because a rhombus has 4 equal sides.
2) The longer diagnal is 24.

I find it helpful to draw myself a little diagram and label it. Devide your rhombus into four equal triangles, and label the sides you know. You'll end up with a ?-12-13. Use the Pythagorean theorum, (a^2+b^2=c^2) and find that the third side is 5. The area of a triangle is 1/2 bh. 12x5=60. 1/2 of 60 is 30. 30x4 (there are four of the little triangles in the rhombus) is 120.

So, the area is 120. =]

Sorry if my explanation was confusing, it's difficult without a diagram.

Answer 2

I found 2 formulas at www.mathopenref.com/rhombusarea.html :

(1)area=base x height
(2)area=d1d2 over 2 (written like a fraction; d=diagonals)

At www.hotmath.com, I found 1/2 ab where a & b are the lengths of the diagonals.

Do these formulas help at all?? I would have tried to figure them out, but geometry was not my strong suit. LOL