how do yu write this ordered pait in mx+b form when the b is constant
(4,-1) (0,3)
(-2,1) (0,1)
2007-07-23 11:47:12 · 3 answers · asked by percy m 1 in Science & Mathematics ➔ Mathematics
p(x,y) is the convention for a point on an X-Y graph.
The slope of a straight line is defined by m = (y1 - y0)/(x1 - x0); where two points are p0 = (x0,y0) = (0,3) and p1 = (x1,y1) = (4,-1) Thus, the slope m = (-1 - 3)/(4 - 0) = -4/4 = -1 for the first two points. By inspection, we see that when x = 0, y = 3, we see that from p0 = (0,3). Putting all that together, we have y = mx + b = -1x + 3. As a check, put x = 4 into the equation to see if you get y = -1, the values at point p1.
Work the second two points the same way.
2007-07-23 12:00:19 · answer #1 · answered by oldprof 7 · 0⤊ 0⤋
y=-x + 3
y =1
2007-07-23 19:25:10 · answer #2 · answered by mramahmedmram 3 · 0⤊ 0⤋
Given two points (x1,y1) and (x2,y2), the slope is
m = rise/run = (y2 - y1) / (x2 - x1). Now you can set up an expression y = mx + b and use one of the points to solve for b, and you can write the full equation.
2007-07-23 18:50:30 · answer #3 · answered by Anonymous · 1⤊ 0⤋