z^2 + 14z + 49
2007-07-23 09:33:43 · 6 answers · asked by Aimee R 1 in Science & Mathematics ➔ Mathematics
z^2+14z+49
=(z+7)(x+7)
=(z+7)^2
2007-07-23 09:36:05 · answer #1 · answered by de4th 4 · 1⤊ 1⤋
What are the factors of 49:
1, 49
7, 7
So, which of these factors, added or subtracted, will equal 14? 7 + 7 = 14! So, we have:
(z + 7)(z + 7)
This is the same as:
(z + 7)^2
2007-07-23 16:38:08 · answer #2 · answered by yeeeehaw 5 · 1⤊ 0⤋
z² + 14z + 49 = 0
z² + 7z + 7z + 49 = 0
z(x + 7) + 7(x + 7) = 0
(x + 7)(z + 7) = 0
- - - - - - - - -s-
2007-07-23 16:53:50 · answer #3 · answered by SAMUEL D 7 · 1⤊ 0⤋
Hi,
For this question, you need to think of which numbers when multiplied together give 49 and when added together give 14.
7x7 = 49
7+7 = 14
Therefore, we can get the following:
(z+7)(z+7) OR (z+7)^2 <==== FINAL ANSWER
I hope that helps you out! Please let me know if you have any other questions!
Sincerely,
Andrew
2007-07-23 16:40:22 · answer #4 · answered by The VC 06 7 · 0⤊ 0⤋
(z+7) (z+7)
or
(z+7)^2
2007-07-23 16:40:30 · answer #5 · answered by -- 2 · 0⤊ 0⤋
(z+7)(z+7)
2007-07-23 16:37:14 · answer #6 · answered by leo 6 · 0⤊ 1⤋