Products & Equation Balancing?

Question

1. Pb(NO3)2+ K2CrO4-----> KNO3 + PbCrO4
2. Fe(NO3)3+NaOH---->Fe(OH)2+NaNO3
3. Cu(NO3)2+NaOH---->Cu(OH)2+NaNO3

Answer 1

Pb(NO3)2+ K2CrO4-----> 2 KNO3 + PbCrO4

Fe(NO3)3+3 NaOH---->Fe(OH)3 +3 NaNO3

Cu(NO3)2+ 2 NaOH---->Cu(OH)2+ 2 NaNO3

Answer 2

1 is correct with just a 2 in front of the KNO3
2 needs Fe(OH)3 and not Fe(OH)2 on the right hand side. Also 3NaOH and 3NaNO3
3 needs a 2 in front of ther NaOH and also a 2 in front of the NaNO3.

Answer 3

You will be required to balance many equations in your chem class. Look at the reactants in equation #1. You have one lead and two nitrates, two potassium and one chromate.
Now look at the products: one potassium (but you need two), one nitrate (but you need two), one lead (that's all you need) and one chromate (that's all you need). All you need to do is have two KNO3 on the product side, and it will be balanced.

Equation 2 has an error. You are showing Fe+3 going to Fe+2 (being reduced) but you are not showing anything being oxidized. The product should be Fe(OH)3. Try balancing this on yourself.

You should be able to do #3 using the same method as before: one copper, three nitrates, one sodium and one hydroxide on the reactant side. You need two hydroxides on the product side and they can only come from NaOH (so you need two NaOH on the reactant side). If you have 2 NaNO3 on the product side, it is balanced.