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(7) ^1.2y^2-6y-13(7)^1/2=0

I need help with this and justifying the solutions and why.

2007-07-23 06:26:54 · 1 answers · asked by littlesoutherner12 1 in Science & Mathematics Mathematics

1 answers

7^1.2 y^2 - 6y -13*sqrt(7)= 0
Use quadratic formula:
x = [6 +/- sqrt(6^2 -4(7^1.2)(-13sqrt(7))]/(2*7^1.2)
x = [6 +/- sqrt(36 +52*7^1.2*sqrt(7))]/2*7^1.2
The above is the exact answer. If you want an approximate answer then
x = [-6 +/- 38.17]/20.66

2007-07-23 06:45:36 · answer #1 · answered by ironduke8159 7 · 0 0

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