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A 720 ml container holds a mixture of red, yellow, and white paint in a 5 : 3 : 12 ratio. How much more red paint than yellow is present in the mixture?
My Answer:



20 ml.

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72 ml.

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108 ml.

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180 ml.

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200 ml.

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2007-07-23 05:09:22 · 4 answers · asked by Michael H 1 in Science & Mathematics Mathematics

4 answers

5+3+12=20

720/20=36 = 1 "unit"

for every 3 units of yellow paint there are 5 units of red therefore the difference is always 2 units (5-3=2)

2x36=72

therefore answer is 72 ml

2007-07-23 05:15:41 · answer #1 · answered by Anonymous · 0 0

The three ratio numbers add up to 20. So each ratio number contains 720/20 = 36 ml. So for red paint there are 36*5 = 180 ml in the container and for yellow paint there are 36*3 = 108 ml. There's 180-108 = 72ml more red paint then yellow paint. The answer is 72.

2007-07-23 05:13:48 · answer #2 · answered by Kyrix 6 · 0 0

5x = Red
3x = Yellow
12x= White
20x = 720 ml
x = 36 ml
5x = 36*5 = 180 ml Red
3x = 3*36 = 108 ml Yellow
Thus 180 - 108 = 72 ml more Red than Yellow

2007-07-23 05:20:34 · answer #3 · answered by ironduke8159 7 · 0 0

108

2007-07-26 12:23:58 · answer #4 · answered by Anonymous · 0 0

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