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Integrate: Sin(3x) Sin(5x) dx

use the table of integrals.

2007-07-23 04:16:53 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

I = ∫ sin(3x) sin(5x) dx
I = ∫ (-1/2) [ cos 8x - cos 2x ] dx
I = (-1/2) [ (1/8)sin 8x - (1/2) sin 2x ] + C
I = (-1/16) sin 8x + (1/4) sin 2x + C

2007-07-23 07:05:54 · answer #1 · answered by Como 7 · 0 0

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