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((24g-144)/(g^2-2g-24)) * ((g^2-3g-28)/(4g-28))

2007-07-23 03:53:31 · 2 answers · asked by just me 1 in Science & Mathematics Mathematics

2 answers

First expression
(24g - 144) / (g - 6) (g + 4)
24 (g - 6) / (g - 6) (g + 4)
24 / (g + 4)

Second expression
(g - 7) (g + 4) / (4 (g - 7))
(1/4) (g + 4)

Multiplying gives:-
6

2007-07-23 08:25:22 · answer #1 · answered by Como 7 · 0 0

24(g-6)/(g+4)(g-6)*(g-7)(g+4)/4(g-7)
Now just cancel out what you can, I will let you finish.

2007-07-23 10:59:38 · answer #2 · answered by leo 6 · 0 1

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