It is given that y = 3x^p^2 - 5p + 7.
Q1) Find the value of x when p = 1 and y = 81.
Q2) If y varies directly as x, find the possible values of p.
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2007-07-23 03:51:59 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
q1. 3x(1)^2 - 5(1) + 7 = 81
3x -5 + 7 = 81
3x = 81 - 7 + 5
3x = 79
x = 79/3 = 26 & 1/3
2007-07-23 03:55:29 · answer #1 · answered by gab BB 6 · 1⤊ 0⤋
y = 3x^p^2 - 5p + 7 and it is given that
y = 81 = 3x^1^2 - 5 + 7
81 = 3x + 2
3x = 81 - 2 = 79
x = 79/3
y = kx (varying directly)
so p^2 = 1
p = 1 or - 1
2007-07-23 10:59:36 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋